3(x+2)+4x-5=7x+(x+1)-6

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Solution for 3(x+2)+4x-5=7x+(x+1)-6 equation:



3(x+2)+4x-5=7x+(x+1)-6
We move all terms to the left:
3(x+2)+4x-5-(7x+(x+1)-6)=0
We add all the numbers together, and all the variables
4x+3(x+2)-(7x+(x+1)-6)-5=0
We multiply parentheses
4x+3x-(7x+(x+1)-6)+6-5=0
We calculate terms in parentheses: -(7x+(x+1)-6), so:
7x+(x+1)-6
We get rid of parentheses
7x+x+1-6
We add all the numbers together, and all the variables
8x-5
Back to the equation:
-(8x-5)
We add all the numbers together, and all the variables
7x-(8x-5)+1=0
We get rid of parentheses
7x-8x+5+1=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6

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