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3(x+2)+4x=7(x+1)-6
We move all terms to the left:
3(x+2)+4x-(7(x+1)-6)=0
We add all the numbers together, and all the variables
4x+3(x+2)-(7(x+1)-6)=0
We multiply parentheses
4x+3x-(7(x+1)-6)+6=0
We calculate terms in parentheses: -(7(x+1)-6), so:We add all the numbers together, and all the variables
7(x+1)-6
We multiply parentheses
7x+7-6
We add all the numbers together, and all the variables
7x+1
Back to the equation:
-(7x+1)
7x-(7x+1)+6=0
We get rid of parentheses
7x-7x-1+6=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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