3(x+2)+5(2+x)=-32

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Solution for 3(x+2)+5(2+x)=-32 equation:



3(x+2)+5(2+x)=-32
We move all terms to the left:
3(x+2)+5(2+x)-(-32)=0
We add all the numbers together, and all the variables
3(x+2)+5(x+2)-(-32)=0
We add all the numbers together, and all the variables
3(x+2)+5(x+2)+32=0
We multiply parentheses
3x+5x+6+10+32=0
We add all the numbers together, and all the variables
8x+48=0
We move all terms containing x to the left, all other terms to the right
8x=-48
x=-48/8
x=-6

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