3(x+2)+5(x-4)=4(2x+3)-6x

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Solution for 3(x+2)+5(x-4)=4(2x+3)-6x equation:



3(x+2)+5(x-4)=4(2x+3)-6x
We move all terms to the left:
3(x+2)+5(x-4)-(4(2x+3)-6x)=0
We multiply parentheses
3x+5x-(4(2x+3)-6x)+6-20=0
We calculate terms in parentheses: -(4(2x+3)-6x), so:
4(2x+3)-6x
We add all the numbers together, and all the variables
-6x+4(2x+3)
We multiply parentheses
-6x+8x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
We add all the numbers together, and all the variables
8x-(2x+12)-14=0
We get rid of parentheses
8x-2x-12-14=0
We add all the numbers together, and all the variables
6x-26=0
We move all terms containing x to the left, all other terms to the right
6x=26
x=26/6
x=4+1/3

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