3(x+2)+5=41

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Solution for 3(x+2)+5=41 equation: 



3(x+2)+5=41

We move all terms to the left:

3(x+2)+5-(41)=0

We add all the numbers together, and all the variables

3(x+2)-36=0

We multiply parentheses

3x+6-36=0

We add all the numbers together, and all the variables

3x-30=0

We move all terms containing x to the left, all other terms to the right

3x=30

x=30/3

x=10

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