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3(x+2)+6=5(x+4)
We move all terms to the left:
3(x+2)+6-(5(x+4))=0
We multiply parentheses
3x-(5(x+4))+6+6=0
We calculate terms in parentheses: -(5(x+4)), so:We add all the numbers together, and all the variables
5(x+4)
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
3x-(5x+20)+12=0
We get rid of parentheses
3x-5x-20+12=0
We add all the numbers together, and all the variables
-2x-8=0
We move all terms containing x to the left, all other terms to the right
-2x=8
x=8/-2
x=-4
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