3(x+2)+7(x-3)-13=-3(x+5)-2(x-7)

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Solution for 3(x+2)+7(x-3)-13=-3(x+5)-2(x-7) equation:



3(x+2)+7(x-3)-13=-3(x+5)-2(x-7)
We move all terms to the left:
3(x+2)+7(x-3)-13-(-3(x+5)-2(x-7))=0
We multiply parentheses
3x+7x-(-3(x+5)-2(x-7))+6-21-13=0
We calculate terms in parentheses: -(-3(x+5)-2(x-7)), so:
-3(x+5)-2(x-7)
We multiply parentheses
-3x-2x-15+14
We add all the numbers together, and all the variables
-5x-1
Back to the equation:
-(-5x-1)
We add all the numbers together, and all the variables
10x-(-5x-1)-28=0
We get rid of parentheses
10x+5x+1-28=0
We add all the numbers together, and all the variables
15x-27=0
We move all terms containing x to the left, all other terms to the right
15x=27
x=27/15
x=1+4/5

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