3(x+2)+7=1/2(6x=2)

Solution for 3(x+2)+7=1/2(6x=2) equation:

3(x+2)+7=1/2(6x=2)

We move all terms to the left:

3(x+2)+7-(1/2(6x)=0


Domain of the equation: 26x+7!=0

We move all terms containing x to the left, all other terms to the right

26x!=-7

x!=-7/26

x!=-7/26

x∈R


We multiply parentheses

3x-(1/26x+7+6=0

We multiply all the terms by the denominator


3x*26x+7+6-(1=0

We add all the numbers together, and all the variables

3x*26x=0

Wy multiply elements

78x^2=0

a = 78; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·78·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{156}=0$