3(x+2)+7x=2(x+11)

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Solution for 3(x+2)+7x=2(x+11) equation: 



3(x+2)+7x=2(x+11)

We move all terms to the left:

3(x+2)+7x-(2(x+11))=0

We add all the numbers together, and all the variables

7x+3(x+2)-(2(x+11))=0

We multiply parentheses

7x+3x-(2(x+11))+6=0



We calculate terms in parentheses: -(2(x+11)), so:

2(x+11)

We multiply parentheses

2x+22

Back to the equation:

-(2x+22)



We add all the numbers together, and all the variables

10x-(2x+22)+6=0

We get rid of parentheses

10x-2x-22+6=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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