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3(x+2)+8=9(x+3)-5
We move all terms to the left:
3(x+2)+8-(9(x+3)-5)=0
We multiply parentheses
3x-(9(x+3)-5)+6+8=0
We calculate terms in parentheses: -(9(x+3)-5), so:We add all the numbers together, and all the variables
9(x+3)-5
We multiply parentheses
9x+27-5
We add all the numbers together, and all the variables
9x+22
Back to the equation:
-(9x+22)
3x-(9x+22)+14=0
We get rid of parentheses
3x-9x-22+14=0
We add all the numbers together, and all the variables
-6x-8=0
We move all terms containing x to the left, all other terms to the right
-6x=8
x=8/-6
x=-1+1/3
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