3(x+2)+x=2(x+3)-2

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Solution for 3(x+2)+x=2(x+3)-2 equation: 



3(x+2)+x=2(x+3)-2

We move all terms to the left:

3(x+2)+x-(2(x+3)-2)=0

We add all the numbers together, and all the variables

x+3(x+2)-(2(x+3)-2)=0

We multiply parentheses

x+3x-(2(x+3)-2)+6=0



We calculate terms in parentheses: -(2(x+3)-2), so:

2(x+3)-2

We multiply parentheses

2x+6-2

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

4x-(2x+4)+6=0

We get rid of parentheses

4x-2x-4+6=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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