3(x+2)+x=2(x+3)-2

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Solution for 3(x+2)+x=2(x+3)-2 equation:



3(x+2)+x=2(x+3)-2
We move all terms to the left:
3(x+2)+x-(2(x+3)-2)=0
We add all the numbers together, and all the variables
x+3(x+2)-(2(x+3)-2)=0
We multiply parentheses
x+3x-(2(x+3)-2)+6=0
We calculate terms in parentheses: -(2(x+3)-2), so:
2(x+3)-2
We multiply parentheses
2x+6-2
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
We add all the numbers together, and all the variables
4x-(2x+4)+6=0
We get rid of parentheses
4x-2x-4+6=0
We add all the numbers together, and all the variables
2x+2=0
We move all terms containing x to the left, all other terms to the right
2x=-2
x=-2/2
x=-1

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