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3(x+2)-(2x+1)=5
We move all terms to the left:
3(x+2)-(2x+1)-(5)=0
We multiply parentheses
3x-(2x+1)+6-5=0
We get rid of parentheses
3x-2x-1+6-5=0
We add all the numbers together, and all the variables
x=0
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