3(x+2)-(2x-5)=3(3-x)

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Solution for 3(x+2)-(2x-5)=3(3-x) equation: 



3(x+2)-(2x-5)=3(3-x)

We move all terms to the left:

3(x+2)-(2x-5)-(3(3-x))=0

We add all the numbers together, and all the variables

3(x+2)-(2x-5)-(3(-1x+3))=0

We multiply parentheses

3x-(2x-5)-(3(-1x+3))+6=0

We get rid of parentheses

3x-2x-(3(-1x+3))+5+6=0



We calculate terms in parentheses: -(3(-1x+3)), so:

3(-1x+3)

We multiply parentheses

-3x+9

Back to the equation:

-(-3x+9)



We add all the numbers together, and all the variables

x-(-3x+9)+11=0

We get rid of parentheses

x+3x-9+11=0

We add all the numbers together, and all the variables

4x+2=0

We move all terms containing x to the left, all other terms to the right

4x=-2

x=-2/4

x=-1/2

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