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3(x+2)-(x+1)=-11
We move all terms to the left:
3(x+2)-(x+1)-(-11)=0
We add all the numbers together, and all the variables
3(x+2)-(x+1)+11=0
We multiply parentheses
3x-(x+1)+6+11=0
We get rid of parentheses
3x-x-1+6+11=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8
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