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3(x+2)-(x+1)=11
We move all terms to the left:
3(x+2)-(x+1)-(11)=0
We multiply parentheses
3x-(x+1)+6-11=0
We get rid of parentheses
3x-x-1+6-11=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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