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3(x+2)-(x-2)=4+2x-8
We move all terms to the left:
3(x+2)-(x-2)-(4+2x-8)=0
We add all the numbers together, and all the variables
3(x+2)-(x-2)-(2x-4)=0
We multiply parentheses
3x-(x-2)-(2x-4)+6=0
We get rid of parentheses
3x-x-2x+2+4+6=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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