3(x+2)-(x-3)=x-5(x+1)+4x

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Solution for 3(x+2)-(x-3)=x-5(x+1)+4x equation: 



3(x+2)-(x-3)=x-5(x+1)+4x

We move all terms to the left:

3(x+2)-(x-3)-(x-5(x+1)+4x)=0

We multiply parentheses

3x-(x-3)-(x-5(x+1)+4x)+6=0

We get rid of parentheses

3x-x-(x-5(x+1)+4x)+3+6=0



We calculate terms in parentheses: -(x-5(x+1)+4x), so:

x-5(x+1)+4x

We add all the numbers together, and all the variables

5x-5(x+1)

We multiply parentheses

5x-5x-5

We add all the numbers together, and all the variables

-5

Back to the equation:

-(-5)



We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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