3(x+2)-(x-3)=x-5-3(x+1)+4

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Solution for 3(x+2)-(x-3)=x-5-3(x+1)+4 equation: 



3(x+2)-(x-3)=x-5-3(x+1)+4

We move all terms to the left:

3(x+2)-(x-3)-(x-5-3(x+1)+4)=0

We multiply parentheses

3x-(x-3)-(x-5-3(x+1)+4)+6=0

We get rid of parentheses

3x-x-(x-5-3(x+1)+4)+3+6=0



We calculate terms in parentheses: -(x-5-3(x+1)+4), so:

x-5-3(x+1)+4

determiningTheFunctionDomain
x-3(x+1)-5+4

We add all the numbers together, and all the variables

x-3(x+1)-1

We multiply parentheses

x-3x-3-1

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We add all the numbers together, and all the variables

2x-(-2x-4)+9=0

We get rid of parentheses

2x+2x+4+9=0

We add all the numbers together, and all the variables

4x+13=0

We move all terms containing x to the left, all other terms to the right

4x=-13

x=-13/4

x=-3+1/4

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