3(x+2)-10+4x=2x+1-3(x-1)

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Solution for 3(x+2)-10+4x=2x+1-3(x-1) equation: 



3(x+2)-10+4x=2x+1-3(x-1)

We move all terms to the left:

3(x+2)-10+4x-(2x+1-3(x-1))=0

We add all the numbers together, and all the variables

4x+3(x+2)-(2x+1-3(x-1))-10=0

We multiply parentheses

4x+3x-(2x+1-3(x-1))+6-10=0



We calculate terms in parentheses: -(2x+1-3(x-1)), so:

2x+1-3(x-1)

determiningTheFunctionDomain
2x-3(x-1)+1

We multiply parentheses

2x-3x+3+1

We add all the numbers together, and all the variables

-1x+4

Back to the equation:

-(-1x+4)



We add all the numbers together, and all the variables

7x-(-1x+4)-4=0

We get rid of parentheses

7x+1x-4-4=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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