3(x+2)-15=7+5(x-4)

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Solution for 3(x+2)-15=7+5(x-4) equation: 



3(x+2)-15=7+5(x-4)

We move all terms to the left:

3(x+2)-15-(7+5(x-4))=0

We multiply parentheses

3x-(7+5(x-4))+6-15=0



We calculate terms in parentheses: -(7+5(x-4)), so:

7+5(x-4)

determiningTheFunctionDomain
5(x-4)+7

We multiply parentheses

5x-20+7

We add all the numbers together, and all the variables

5x-13

Back to the equation:

-(5x-13)



We add all the numbers together, and all the variables

3x-(5x-13)-9=0

We get rid of parentheses

3x-5x+13-9=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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