3(x+2)-1=(2x+3)-7

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Solution for 3(x+2)-1=(2x+3)-7 equation: 



3(x+2)-1=(2x+3)-7

We move all terms to the left:

3(x+2)-1-((2x+3)-7)=0

We multiply parentheses

3x-((2x+3)-7)+6-1=0



We calculate terms in parentheses: -((2x+3)-7), so:

(2x+3)-7

We get rid of parentheses

2x+3-7

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

3x-(2x-4)+5=0

We get rid of parentheses

3x-2x+4+5=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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