3(x+2)-2(x+1)=-8

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Solution for 3(x+2)-2(x+1)=-8 equation: 



3(x+2)-2(x+1)=-8

We move all terms to the left:

3(x+2)-2(x+1)-(-8)=0

We add all the numbers together, and all the variables

3(x+2)-2(x+1)+8=0

We multiply parentheses

3x-2x+6-2+8=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12

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