3(x+2)-2(x-1)=4(x+3)+3(x-4)-4

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Solution for 3(x+2)-2(x-1)=4(x+3)+3(x-4)-4 equation: 



3(x+2)-2(x-1)=4(x+3)+3(x-4)-4

We move all terms to the left:

3(x+2)-2(x-1)-(4(x+3)+3(x-4)-4)=0

We multiply parentheses

3x-2x-(4(x+3)+3(x-4)-4)+6+2=0



We calculate terms in parentheses: -(4(x+3)+3(x-4)-4), so:

4(x+3)+3(x-4)-4

We multiply parentheses

4x+3x+12-12-4

We add all the numbers together, and all the variables

7x-4

Back to the equation:

-(7x-4)



We add all the numbers together, and all the variables

x-(7x-4)+8=0

We get rid of parentheses

x-7x+4+8=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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