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3(x+2)-2(x-1)=5(x-5)
We move all terms to the left:
3(x+2)-2(x-1)-(5(x-5))=0
We multiply parentheses
3x-2x-(5(x-5))+6+2=0
We calculate terms in parentheses: -(5(x-5)), so:We add all the numbers together, and all the variables
5(x-5)
We multiply parentheses
5x-25
Back to the equation:
-(5x-25)
x-(5x-25)+8=0
We get rid of parentheses
x-5x+25+8=0
We add all the numbers together, and all the variables
-4x+33=0
We move all terms containing x to the left, all other terms to the right
-4x=-33
x=-33/-4
x=8+1/4
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