3(x+2)-4(2x-3)=19x+6

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Solution for 3(x+2)-4(2x-3)=19x+6 equation: 



3(x+2)-4(2x-3)=19x+6

We move all terms to the left:

3(x+2)-4(2x-3)-(19x+6)=0

We multiply parentheses

3x-8x-(19x+6)+6+12=0

We get rid of parentheses

3x-8x-19x-6+6+12=0

We add all the numbers together, and all the variables

-24x+12=0

We move all terms containing x to the left, all other terms to the right

-24x=-12

x=-12/-24

x=1/2

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