3(x+2)-4(x+1)+5=5(x+3)-8

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Solution for 3(x+2)-4(x+1)+5=5(x+3)-8 equation: 



3(x+2)-4(x+1)+5=5(x+3)-8

We move all terms to the left:

3(x+2)-4(x+1)+5-(5(x+3)-8)=0

We multiply parentheses

3x-4x-(5(x+3)-8)+6-4+5=0



We calculate terms in parentheses: -(5(x+3)-8), so:

5(x+3)-8

We multiply parentheses

5x+15-8

We add all the numbers together, and all the variables

5x+7

Back to the equation:

-(5x+7)



We add all the numbers together, and all the variables

-1x-(5x+7)+7=0

We get rid of parentheses

-1x-5x-7+7=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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