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3(x+2)-4=2(x-1)+1
We move all terms to the left:
3(x+2)-4-(2(x-1)+1)=0
We multiply parentheses
3x-(2(x-1)+1)+6-4=0
We calculate terms in parentheses: -(2(x-1)+1), so:We add all the numbers together, and all the variables
2(x-1)+1
We multiply parentheses
2x-2+1
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
3x-(2x-1)+2=0
We get rid of parentheses
3x-2x+1+2=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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