3(x+2)-5(2x+5)=3(0x+7)

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Solution for 3(x+2)-5(2x+5)=3(0x+7) equation:



3(x+2)-5(2x+5)=3(0x+7)
We move all terms to the left:
3(x+2)-5(2x+5)-(3(0x+7))=0
We add all the numbers together, and all the variables
3(x+2)-5(2x+5)-(3(x+7))=0
We multiply parentheses
3x-10x-(3(x+7))+6-25=0
We calculate terms in parentheses: -(3(x+7)), so:
3(x+7)
We multiply parentheses
3x+21
Back to the equation:
-(3x+21)
We add all the numbers together, and all the variables
-7x-(3x+21)-19=0
We get rid of parentheses
-7x-3x-21-19=0
We add all the numbers together, and all the variables
-10x-40=0
We move all terms containing x to the left, all other terms to the right
-10x=40
x=40/-10
x=-4

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