3(x+2)-5(2x+5)=7(3-2x)

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Solution for 3(x+2)-5(2x+5)=7(3-2x) equation: 



3(x+2)-5(2x+5)=7(3-2x)

We move all terms to the left:

3(x+2)-5(2x+5)-(7(3-2x))=0

We add all the numbers together, and all the variables

3(x+2)-5(2x+5)-(7(-2x+3))=0

We multiply parentheses

3x-10x-(7(-2x+3))+6-25=0



We calculate terms in parentheses: -(7(-2x+3)), so:

7(-2x+3)

We multiply parentheses

-14x+21

Back to the equation:

-(-14x+21)



We add all the numbers together, and all the variables

-7x-(-14x+21)-19=0

We get rid of parentheses

-7x+14x-21-19=0

We add all the numbers together, and all the variables

7x-40=0

We move all terms containing x to the left, all other terms to the right

7x=40

x=40/7

x=5+5/7

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