3(x+2)-5(3x-4)=38

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Solution for 3(x+2)-5(3x-4)=38 equation: 



3(x+2)-5(3x-4)=38

We move all terms to the left:

3(x+2)-5(3x-4)-(38)=0

We multiply parentheses

3x-15x+6+20-38=0

We add all the numbers together, and all the variables

-12x-12=0

We move all terms containing x to the left, all other terms to the right

-12x=12

x=12/-12

x=-1

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