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3(x+2)-5(3x-4)=38
We move all terms to the left:
3(x+2)-5(3x-4)-(38)=0
We multiply parentheses
3x-15x+6+20-38=0
We add all the numbers together, and all the variables
-12x-12=0
We move all terms containing x to the left, all other terms to the right
-12x=12
x=12/-12
x=-1
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