3(x+2)-5(x-4)=10

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Solution for 3(x+2)-5(x-4)=10 equation: 



3(x+2)-5(x-4)=10

We move all terms to the left:

3(x+2)-5(x-4)-(10)=0

We multiply parentheses

3x-5x+6+20-10=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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