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3(x+2)-6=-2(x+1)+x
We move all terms to the left:
3(x+2)-6-(-2(x+1)+x)=0
We multiply parentheses
3x-(-2(x+1)+x)+6-6=0
We calculate terms in parentheses: -(-2(x+1)+x), so:We add all the numbers together, and all the variables
-2(x+1)+x
We add all the numbers together, and all the variables
x-2(x+1)
We multiply parentheses
x-2x-2
We add all the numbers together, and all the variables
-1x-2
Back to the equation:
-(-1x-2)
3x-(-1x-2)=0
We get rid of parentheses
3x+1x+2=0
We add all the numbers together, and all the variables
4x+2=0
We move all terms containing x to the left, all other terms to the right
4x=-2
x=-2/4
x=-1/2
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