3(x+2)-6x=4(x-3)+6x

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Solution for 3(x+2)-6x=4(x-3)+6x equation: 



3(x+2)-6x=4(x-3)+6x

We move all terms to the left:

3(x+2)-6x-(4(x-3)+6x)=0

We add all the numbers together, and all the variables

-6x+3(x+2)-(4(x-3)+6x)=0

We multiply parentheses

-6x+3x-(4(x-3)+6x)+6=0



We calculate terms in parentheses: -(4(x-3)+6x), so:

4(x-3)+6x

We add all the numbers together, and all the variables

6x+4(x-3)

We multiply parentheses

6x+4x-12

We add all the numbers together, and all the variables

10x-12

Back to the equation:

-(10x-12)



We add all the numbers together, and all the variables

-3x-(10x-12)+6=0

We get rid of parentheses

-3x-10x+12+6=0

We add all the numbers together, and all the variables

-13x+18=0

We move all terms containing x to the left, all other terms to the right

-13x=-18

x=-18/-13

x=1+5/13

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