3(x+2)-7(2x-4)=4(3x-1)

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Solution for 3(x+2)-7(2x-4)=4(3x-1) equation: 



3(x+2)-7(2x-4)=4(3x-1)

We move all terms to the left:

3(x+2)-7(2x-4)-(4(3x-1))=0

We multiply parentheses

3x-14x-(4(3x-1))+6+28=0



We calculate terms in parentheses: -(4(3x-1)), so:

4(3x-1)

We multiply parentheses

12x-4

Back to the equation:

-(12x-4)



We add all the numbers together, and all the variables

-11x-(12x-4)+34=0

We get rid of parentheses

-11x-12x+4+34=0

We add all the numbers together, and all the variables

-23x+38=0

We move all terms containing x to the left, all other terms to the right

-23x=-38

x=-38/-23

x=1+15/23

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