3(x+2)-7(2x-4)=4(3x-1)

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Solution for 3(x+2)-7(2x-4)=4(3x-1) equation:



3(x+2)-7(2x-4)=4(3x-1)
We move all terms to the left:
3(x+2)-7(2x-4)-(4(3x-1))=0
We multiply parentheses
3x-14x-(4(3x-1))+6+28=0
We calculate terms in parentheses: -(4(3x-1)), so:
4(3x-1)
We multiply parentheses
12x-4
Back to the equation:
-(12x-4)
We add all the numbers together, and all the variables
-11x-(12x-4)+34=0
We get rid of parentheses
-11x-12x+4+34=0
We add all the numbers together, and all the variables
-23x+38=0
We move all terms containing x to the left, all other terms to the right
-23x=-38
x=-38/-23
x=1+15/23

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