3(x+2)-7=3(x-1)+2

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Solution for 3(x+2)-7=3(x-1)+2 equation: 


Simplifying
3(x + 2) + -7 = 3(x + -1) + 2

Reorder the terms:
3(2 + x) + -7 = 3(x + -1) + 2
(2 * 3 + x * 3) + -7 = 3(x + -1) + 2
(6 + 3x) + -7 = 3(x + -1) + 2

Reorder the terms:
6 + -7 + 3x = 3(x + -1) + 2

Combine like terms: 6 + -7 = -1
-1 + 3x = 3(x + -1) + 2

Reorder the terms:
-1 + 3x = 3(-1 + x) + 2
-1 + 3x = (-1 * 3 + x * 3) + 2
-1 + 3x = (-3 + 3x) + 2

Reorder the terms:
-1 + 3x = -3 + 2 + 3x

Combine like terms: -3 + 2 = -1
-1 + 3x = -1 + 3x

Add '1' to each side of the equation.
-1 + 1 + 3x = -1 + 1 + 3x

Combine like terms: -1 + 1 = 0
0 + 3x = -1 + 1 + 3x
3x = -1 + 1 + 3x

Combine like terms: -1 + 1 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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