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3(x+2)-7=4(2x-4)-2x
We move all terms to the left:
3(x+2)-7-(4(2x-4)-2x)=0
We multiply parentheses
3x-(4(2x-4)-2x)+6-7=0
We calculate terms in parentheses: -(4(2x-4)-2x), so:We add all the numbers together, and all the variables
4(2x-4)-2x
We add all the numbers together, and all the variables
-2x+4(2x-4)
We multiply parentheses
-2x+8x-16
We add all the numbers together, and all the variables
6x-16
Back to the equation:
-(6x-16)
3x-(6x-16)-1=0
We get rid of parentheses
3x-6x+16-1=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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