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3(x+2)-7x=-6(x-2)-x
We move all terms to the left:
3(x+2)-7x-(-6(x-2)-x)=0
We add all the numbers together, and all the variables
-7x+3(x+2)-(-6(x-2)-x)=0
We multiply parentheses
-7x+3x-(-6(x-2)-x)+6=0
We calculate terms in parentheses: -(-6(x-2)-x), so:We add all the numbers together, and all the variables
-6(x-2)-x
We add all the numbers together, and all the variables
-1x-6(x-2)
We multiply parentheses
-1x-6x+12
We add all the numbers together, and all the variables
-7x+12
Back to the equation:
-(-7x+12)
-4x-(-7x+12)+6=0
We get rid of parentheses
-4x+7x-12+6=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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