3(x+2)-7x=16-(3x+8)

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Solution for 3(x+2)-7x=16-(3x+8) equation: 



3(x+2)-7x=16-(3x+8)

We move all terms to the left:

3(x+2)-7x-(16-(3x+8))=0

We add all the numbers together, and all the variables

-7x+3(x+2)-(16-(3x+8))=0

We multiply parentheses

-7x+3x-(16-(3x+8))+6=0



We calculate terms in parentheses: -(16-(3x+8)), so:

16-(3x+8)

determiningTheFunctionDomain
-(3x+8)+16

We get rid of parentheses

-3x-8+16

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We add all the numbers together, and all the variables

-4x-(-3x+8)+6=0

We get rid of parentheses

-4x+3x-8+6=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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