3(x+2)-8(2x-7)=16

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Solution for 3(x+2)-8(2x-7)=16 equation: 



3(x+2)-8(2x-7)=16

We move all terms to the left:

3(x+2)-8(2x-7)-(16)=0

We multiply parentheses

3x-16x+6+56-16=0

We add all the numbers together, and all the variables

-13x+46=0

We move all terms containing x to the left, all other terms to the right

-13x=-46

x=-46/-13

x=3+7/13

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