3(x+2)-9=15-4(5x-2)

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Solution for 3(x+2)-9=15-4(5x-2) equation: 



3(x+2)-9=15-4(5x-2)

We move all terms to the left:

3(x+2)-9-(15-4(5x-2))=0

We multiply parentheses

3x-(15-4(5x-2))+6-9=0



We calculate terms in parentheses: -(15-4(5x-2)), so:

15-4(5x-2)

determiningTheFunctionDomain
-4(5x-2)+15

We multiply parentheses

-20x+8+15

We add all the numbers together, and all the variables

-20x+23

Back to the equation:

-(-20x+23)



We add all the numbers together, and all the variables

3x-(-20x+23)-3=0

We get rid of parentheses

3x+20x-23-3=0

We add all the numbers together, and all the variables

23x-26=0

We move all terms containing x to the left, all other terms to the right

23x=26

x=26/23

x=1+3/23

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