3(x+2)-x+1=19

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Solution for 3(x+2)-x+1=19 equation: 



3(x+2)-x+1=19

We move all terms to the left:

3(x+2)-x+1-(19)=0

We add all the numbers together, and all the variables

-1x+3(x+2)-18=0

We multiply parentheses

-1x+3x+6-18=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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