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3(x+2)-x=2(x-1
We move all terms to the left:
3(x+2)-x-(2(x-1)=0
We add all the numbers together, and all the variables
-1x+3(x+2)-(2(x-1)=0
We multiply parentheses
-1x+3x-(2(x-1)+6=0
We add all the numbers together, and all the variables
2x-(2(x-1)+6=0
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