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3(x+2)/5=2x-4
We move all terms to the left:
3(x+2)/5-(2x-4)=0
We get rid of parentheses
3(x+2)/5-2x+4=0
We multiply all the terms by the denominator
3(x+2)-2x*5+4*5=0
We add all the numbers together, and all the variables
3(x+2)-2x*5+20=0
We multiply parentheses
3x-2x*5+6+20=0
Wy multiply elements
3x-10x+6+20=0
We add all the numbers together, and all the variables
-7x+26=0
We move all terms containing x to the left, all other terms to the right
-7x=-26
x=-26/-7
x=3+5/7
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