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3(x+2)5x=6+8
We move all terms to the left:
3(x+2)5x-(6+8)=0
We add all the numbers together, and all the variables
3(x+2)5x-14=0
We multiply parentheses
15x^2+30x-14=0
a = 15; b = 30; c = -14;
Δ = b2-4ac
Δ = 302-4·15·(-14)
Δ = 1740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1740}=\sqrt{4*435}=\sqrt{4}*\sqrt{435}=2\sqrt{435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{435}}{2*15}=\frac{-30-2\sqrt{435}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{435}}{2*15}=\frac{-30+2\sqrt{435}}{30} $
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