3(x+2)=(10-x)+11

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Solution for 3(x+2)=(10-x)+11 equation: 



3(x+2)=(10-x)+11

We move all terms to the left:

3(x+2)-((10-x)+11)=0

We add all the numbers together, and all the variables

3(x+2)-((-1x+10)+11)=0

We multiply parentheses

3x-((-1x+10)+11)+6=0



We calculate terms in parentheses: -((-1x+10)+11), so:

(-1x+10)+11

We get rid of parentheses

-1x+10+11

We add all the numbers together, and all the variables

-1x+21

Back to the equation:

-(-1x+21)



We get rid of parentheses

3x+1x-21+6=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

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