3(x+2)=(x+2)*3

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Solution for 3(x+2)=(x+2)*3 equation:



3(x+2)=(x+2)*3
We move all terms to the left:
3(x+2)-((x+2)*3)=0
We multiply parentheses
3x-((x+2)*3)+6=0
We calculate terms in parentheses: -((x+2)*3), so:
(x+2)*3
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
We get rid of parentheses
3x-3x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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