3(x+2)=+5+2(x-3)

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Solution for 3(x+2)=+5+2(x-3) equation: 



3(x+2)=+5+2(x-3)

We move all terms to the left:

3(x+2)-(+5+2(x-3))=0

We multiply parentheses

3x-(+5+2(x-3))+6=0



We calculate terms in parentheses: -(+5+2(x-3)), so:

+5+2(x-3)

determiningTheFunctionDomain
2(x-3)+5

We multiply parentheses

2x-6+5

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

3x-2x+1+6=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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