3(x+2)=-4(x-12)

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Solution for 3(x+2)=-4(x-12) equation:



3(x+2)=-4(x-12)
We move all terms to the left:
3(x+2)-(-4(x-12))=0
We multiply parentheses
3x-(-4(x-12))+6=0
We calculate terms in parentheses: -(-4(x-12)), so:
-4(x-12)
We multiply parentheses
-4x+48
Back to the equation:
-(-4x+48)
We get rid of parentheses
3x+4x-48+6=0
We add all the numbers together, and all the variables
7x-42=0
We move all terms containing x to the left, all other terms to the right
7x=42
x=42/7
x=6

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