3(x+2)=-5-2(x-2)

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Solution for 3(x+2)=-5-2(x-2) equation: 



3(x+2)=-5-2(x-2)

We move all terms to the left:

3(x+2)-(-5-2(x-2))=0

We multiply parentheses

3x-(-5-2(x-2))+6=0



We calculate terms in parentheses: -(-5-2(x-2)), so:

-5-2(x-2)

determiningTheFunctionDomain
-2(x-2)-5

We multiply parentheses

-2x+4-5

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

3x+2x+1+6=0

We add all the numbers together, and all the variables

5x+7=0

We move all terms containing x to the left, all other terms to the right

5x=-7

x=-7/5

x=-1+2/5

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