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3(x+2)=-5-2(x-6)
We move all terms to the left:
3(x+2)-(-5-2(x-6))=0
We multiply parentheses
3x-(-5-2(x-6))+6=0
We calculate terms in parentheses: -(-5-2(x-6)), so:We get rid of parentheses
-5-2(x-6)
determiningTheFunctionDomain -2(x-6)-5
We multiply parentheses
-2x+12-5
We add all the numbers together, and all the variables
-2x+7
Back to the equation:
-(-2x+7)
3x+2x-7+6=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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